Single Discount Equivalent
Those are the formula
r = 1 – r( 1- r1) (1 – r2) (1 – r3)
Example:
1) A car is advertised at RM50000 less 20%, 10% and 5%. Find
(a) the single trade equivalent
(b) the net price
From r = 1 – r( 1- r1) (1 – r2) (1 – r3), we get
(a) singe discount equivalent = 1- ( 1 – 0.20 ) ( 1- 0.10 ) ( 1 – 0.05 )
= 1 - ( 0.80 ) ( 0.90 ) ( 0.95 )
= 1 – 0.84
= 0.316
= 31.6%
(b) From NP = L(1-r), we get
= 50000 ( 1 – 31.6% )
= RM 34200
2) Find the single discount equivalent of 20% and 3.5%.
From r = 1 – r( 1- r1) (1 – r2) (1 – r3), we get
r = 1 ( 1 – 20% ) ( 1- 3.5% )
=0.772
=77.2%
2 comments:
aduh ida aq bingung nih kasih commnet nga tau matematika sih, hmmmm......... apa ya ini rumus buat minuman coca cola yaa hehehhehe
pity you got a negative comment from hilmandjayadi. But it is quite funny. Anyway, may be you can improve the content of your blog by discussing more interesting topic, not only formulae! Keep trying!!
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